5x^2+10x-9=3x

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Solution for 5x^2+10x-9=3x equation:



5x^2+10x-9=3x
We move all terms to the left:
5x^2+10x-9-(3x)=0
We add all the numbers together, and all the variables
5x^2+7x-9=0
a = 5; b = 7; c = -9;
Δ = b2-4ac
Δ = 72-4·5·(-9)
Δ = 229
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{229}}{2*5}=\frac{-7-\sqrt{229}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{229}}{2*5}=\frac{-7+\sqrt{229}}{10} $

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